If 236 g of copperII nitrate was produced in reaction 1 from

If 2.36 g of copper(II) nitrate was produced in reaction (1) from 0.800 g of elemental copper, _____ mole of sodium nitrate would be produced in reaction (2). (Be sure the equations are balanced.)

(1) Cu(s) + 4HNO₃(aq) --> Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(l)

(2) Cu(NO₃)₂(aq) + 2NaOH(aq) --> Cu(OH)₂(s) + 2NaNO₃(aq)

Solution

2.36 gms of copper nitrate = 0.01258 moles

for one mole of copper nitrate 2 moles of sodium nitrate are produced

so for 0.01258 moles 0.02516 moles of sodium nitrate is produced.