Homework SourseGiven the following rate law how does the rate of reaction c
Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled?
Rate = K [ X ]^2 [ Y ]^3
a)The rate of the rxn will increase by factor of 2.
b) “. “. “. “. “. “. “. “. 4.
c). “. “. “. “. “. “. “. “. 8.
d). “. “. “. “. “. “. “. “. 9.
Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled?
Rate = K [ X ]^2 [ Y ]^3
a)The rate of the rxn will increase by factor of 2.
b) “. “. “. “. “. “. “. “. 4.
c). “. “. “. “. “. “. “. “. 8.
d). “. “. “. “. “. “. “. “. 9.
Rate = K [ X ]^2 [ Y ]^3
a)The rate of the rxn will increase by factor of 2.
b) “. “. “. “. “. “. “. “. 4.
c). “. “. “. “. “. “. “. “. 8.
d). “. “. “. “. “. “. “. “. 9.
Solution
Given Rate law is:
rate = k[X]^2[Y]^3
rate new / rate old = ([X]new/[X]old)^2*([Y]new/[Y]old)^3
here:
[X]new/[X]old = 1
[Y]new/[Y]old = 2
putting values
rate new / rate old = (1.0)^2*(2.0)^3
rate new / rate old = 8
Answer: c
![Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = K [ X ]^2 [ Y ]^3 a)The rate of the rxn will in](/WebImages/45/given-the-following-rate-law-how-does-the-rate-of-reaction-c-1140389-1761611490-0.webp "Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = K [ X ]^2 [ Y ]^3 a)The rate of the rxn will in")
