An initial investment of 9000 grows at an annual interest ra
An initial investment of $9000 grows at an annual interest rate of 5% compounded continuously. How long will it take to double the investment?
1 year
14.40 years
13.86 years
14.86 years
13.40 years
| 1 year | ||
| 14.40 years | ||
| 13.86 years | ||
| 14.86 years | ||
| 13.40 years |
Solution
Amount = principale^(rate*time)
So, 18000 = 90000e^(0.05t)
2 = e^(0.05t)
take natural log on both sides:
ln2 = 0.05t
t = 13.86 years
