Homework SourseFind the equation of the normal line to the graph of the equ
Find the equation of the normal line to the graph of the equation 4x^2 - y^2 + 3z^2 = 10 at the point P(2,-3,1) Can someone please show me the steps to getting the equation thanks!
Solution
equation = 4x^2 - y^2 + 3z^2 = 10
at the point we have (2,-3,1)
F = 8x - 2y + 6z
Equation of the normal line is given by
r(t) = (2,-3,1) + t F(2,-3,1).
r(t) = (2,-3,1) + t(16, 6, 6)
x = 2 + 16t , y = -3 + 6t , z = 1 + 6t
this is the normal equation in parametric form
