lease follow the following steps to start and finish the tes

lease follow the following steps to start and finish the test: ) Confirm start ) Click save progress and then click again on next page ) When you are done, click on Confirm Finish elect only one correct answer for each question. Question Incomplete Question Complete oxidation from lowest to hight Rank the following compounds in order of increasing oxidation level (from lowest to highest). CH COOH CH3CHs CH CHO CH2-CH2 O D. II

Solution

During estimating of the oxidation state,we consider that homonuclear bond connectivity(for this case C-C) does not contribute in the calculation.

All the compounds are neutral.

Now we no, that oxidation number of H = +1

oxidation no of O = -2

Say, the oxidation state of the carbonyl carbon (i.e C=O) in the 1st compund i.e CH₃COOH is \'X\' so taking up our consideration we will calculate only the COOH part.

X + 2*(-2) + 1(+1) = 0

X = +3

For CH₃CH₃ say the oxidation state of the 2 carbon same asnd it is \'Y\"

So, 2Y+6(+1) = 0

Y= -3

For CH₃CHO we\'ll consider the CHO part and say the oxidation state of the carbon = Z

so, Z+1(-2)+1(+1)=0

Z =+1

For CH₂=CH₂ the oxidation state of each carbon is same and say it is \'W\'

so, 2W + 1(+1) = 0

W = -2

So, I has oxidation state = +3

II has oxidation state = -3

III has oxidation state = +1

IV has oxidation state = -2

So, arranging the four compounds according to oxidation states option \'D\' is the right answer.