Show the calculations for preparing 004 N 100 mL from 25 HCl

Show the calculations for preparing 0.04 N (100 mL) from 25% HCl by volume.

Solution

So we have to prepare 0.04 N HCl ,100 ml from 25% HCl by volume

25% HCl by volume means 25 ml of HCl/100 ml of solution .

Density of HCl is 1.19g/ml

so we can convert 25 % HCl as 25*1.19 gms /100 ml=29.75g/100ml=(29.75/36.5)mol/0.1 litres=8.15 N

so N₂=8.15 N,V₂=?

N₁=0.04 N,V₁=100 ml

so applying N₁V₁=N₂V₂

WE GET V₂=N₁V₁/N₂=(0.04*100)/8.15=0.5 ml HCl

So,0.5 ml HClshould be added into 99.5 ml of water to make up 100 ml solution