Consider the family of vectors B 1 1 0 1 0 1 0 1 1 R3 Determ

Consider the family of vectors B:= {(1 1 0), (1 0 1), (0 1 1)} R^3. Determine whether or not the collection B is linearly independent family in R^3. Is the family B a basis of the (real) vector space R^3 under the standard addition and multiplication by scalars? (Justify your answer!) Determine whether B is a collection of orthogonal vectors. If not, orthogonalize it. (Show your work and state the name of the procedure you use!) Orthonormalize the family obtained in part (c) above.

Solution

Let v1 = (1,1,0)T , v2 = =(1,0,1)T , and v3 = ( 0,1,1)T. Let A be the matrix with v1, v2,v3 as its 1st, 2nd and 3rd columns. We will reduce A to its RREF as undeR:

1. Add -1 times the 1st row to the 2nd row; 2. Multiply the 2nd row by -1

3.. Add -1 times the 2nd row to the 3rd row; 4. Multiply the 3rd row by ½

5. Add 1 times the 3rd row to the 2nd row ; 6. Add -1 times the 2nd row to the 1st row

Then the RREF of A is I3. This implies that:

a. The collection of vectors in B is a linearly independent family in R3.

b. The collection of vectors in B forms a basis for R3 under the standard addition and scalar multiplication.

c. Since v1.v2=(1,1,0)T.(1,0,1)T = 1 0, hence B is not a collection of orthogonal vectors. Let u1 = v1 , u2 = v2 – Proju1(v2) = v2 – [(v2.u1)/(u1.u1)]u1 = (1,0,1)T- 1/2(1,1,0)T = (1/2, -1/2, 1)T and u3= v3- Proju1(v3) - Proju2(v3) = v3-[(v3.u1)/(u1.u1)]u1-[(v3.u2)/(u2.u2)]u2= v3-(1/2)u1- (1/3)u2= (0,1,1)T–(1/2,1/2,0)T– (1/6, -1/6, 1/3)T= (-2/3, 2/3, 2/3)T. Thus, an orthogonal basis for B is { (1,1,0)T, (1/2, -1/2, 1)T, (-2/3, 2/3, 2/3)T} . The Gram- Schimdt process has been used for orthogonalization.

d. Let w1 = u1/||u1|| = (1/2, 1/2,0)T , w2 = u2/||u2||= (1/6 , -1/6, 2/3)T, w3 = u3/||u3|| = (-1/3, 1/3, 1/3)T. Then { w1 ,w2, w3} is an orthonormal basis for B.

 Consider the family of vectors B:= {(1 1 0), (1 0 1), (0 1 1)} R^3. Determine whether or not the collection B is linearly independent family in R^3. Is the fam

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