Homework SourseI changed the original equation to be t213 2t312 I then mul
I changed the original equation to be (t^2)^1/3 + 2*(t^3)^1/2.
I then multiplied the exponents to get t^2/3 + 2*t^3/2.
I then took the derivative of t^2/3 + 2*t^3/2.
My result was 2/3*(t^-1/3) + 3*(t^1/2).
Is this the correct method?
I then multiplied the exponents to get t^2/3 + 2*t^3/2.
I then took the derivative of t^2/3 + 2*t^3/2.
My result was 2/3*(t^-1/3) + 3*(t^1/2).
Is this the correct method?
Solution
you did correct (t^2)^1/3 + 2*(t^3)^1/2. = t^(2/3) + 2*t^(3/2). derivative= (2/3)*(t^-1/3) + 3*(t^1/2)
