Twice a first number decreased by a second number is 11 The

Twice a first number decreased by a second number is 11. The first number increased by twice the second number is 18. Find the numbers. The numbers are (Use a comma to separate answers as needed.)

Solution

Let x be the first number and

y be the second number

2x-y=11

x+2y=18

4x-2y=22

x+2y=18

Adding abive equations

5x=40

x=8

8+2y=18

y=5