#13 & 14 please
A bar having a length of 5 in. and cross-sectional area of 0.7 in^2 is subjected to an axial force of 8000 lb. If the bar stretches 0.002 in., determine the modulus of elasticity of the material. The material has linear elastic behavior. The rigid pipe is supported by a pin at A .and an A-36 steel guy wire BD. If the wire bus it diameter of 0.25 in., determine how much it stretches when a load of P = 600 lb acts on the pipe.
#13 solution ,
strain = change in lenght / initial lenght. = 0.002 / 5 = 0.0004 .
modulus of elasticity, E = stress / strain = axial foece /( area * strain ) = 8000/( 0.7 * 0.0004 ) = 28571428.5 psi (Ans.)
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