Please provide resolution steps Question 5 A company that b

Please provide resolution steps

Question 5 - A company that bakes chocolate chip cookies averages 5.2 chocolate chips per cookie. Assume that the number of chocolate chips per cookie follows the Poisson distribution. What is the probability that a randomly selected cookie will contain one or two chocolate chips?

Question 10 -  A novel on the Amazon.com web site has the following ratings, in number of stars, from reviewers:

What is the probability that a randomly selected review is more than 3 stars?

Question 11 - According to LIMRA, 77% of husband-wife families with kids under 18 years old have life insurance. A random sample of six husband-wife families was selected. What is the probability that exactly four families have life insurance?

Question 16 - Dwight Howard plays center in the National Basketball Association and averaged 1.8 blocked shots per game during a recent season. Assume that the number of blocked shots per game follows the Poisson distribution. What is the probability that Dwight Howard will block two or three shots during the next game?

Question 20 -  The following table shows the number of pieces of junk mail that arrives in my mailbox each day.

What is the mean number of pieces of junk mail received per day?

Question 21 -  The following table shows the number of pieces of junk mail that arrives in my mailbox each day.

What is the standard deviation for the number of pieces of junk mail received per day?

0.55

0.21

Solution

5)

Poisson distribution for mean of 5.2 having one or two cookies will be

P (X = 1) + P (X = 2)

= 0.02868 + 0.07458

= 0.10326

= 10.326%

10)

Total number of reviews = 7 + 4 + 20 + 9 + 10 = 50 ratings

More than 3 stars rating = 9 + 10 = 19

Probability = 19 / 50

= 0.38

11)

probability of having insurance = 0.77

probability of not having one = 0.23

Thus, probability of exactly 4 people having it out of 6 = ⁶C₄ (0.77)⁴ (0.23)² = 0.2789

= 27.89%

16)

Poisson distribution for mean of 1.8 having two or three blocked shots will be

P (X = 2) + P (X = 3)

= 0.26778 + 0.16067

= 0.42845

= 42.845%

20)

Mean = (2*2) + (3*14) + (4*6) + (5*16) + (6*12) / 50 = 4.44

Variance = 1.5264

Hope this helps.