9 12 pts Consider the following reaction 2 PHb When 0550 mo

9. (12 pts) Consider the following reaction: 2 PHb () When 0.550 mole of PH3 is placed in a 0.100 L container and the system equilibrium, 0.243 mole of P2 is present in the equilibrium mixture. alw Calculate K.c 2(g) Kc=455x1( ed together in a 5.00 Lr 10. (10 pts) Consider the following equilibrium: 2 CO2 (g) 2 CO (g) + If 3.50 moles of CO2, 2.00 moles of CO, and 7.75 moles of O2 are mix vessel, is the system at equilibrium? moves toward equilibrium? Show your work If not, will oxygen gas be consumed or produced as the .).somouls

Solution

Ans 9

Balanced equation with ICE table

2PH3 = P2 + 3H2

I 0.550

C - 2x +x +3x

E 0.550-2x +x +3x

After equilibrium

Moles of P2 = 0.243 = x

Concentration of [P2] = 0.243/0.1 = 2.43 M

Moles of H2 = 3*0.243 = 0.729 mol

Concentration of [H2] = 0.729/0.1 = 7.29 M

Moles of PH3 = 0.550-2x = 0.550 - 2*0.243 = 0.064

Concentration of [PH3] = 0.064/0.1 = 0.64 M

Equilibrium constant expression of the reaction

Kc = [P2] [H2]³ / [PH3]²

= 2.43*7.29*7.29*7.29/0.64*0.64

= 2298.42

= 2.298*10^3