Margie threw a ball upwards while standing on a platform 20

. Margie threw a ball upwards while standing on a platform 200 ft. off of the ground. The trajectory after t seconds follows the equation:

b. How long will it take the ball reach its maximum height?

c. How long will it take the ball to hit the ground?

h(t) = -32t/50^2 + 6t +200

a) Maximum heigt : at t = -b/2a

t = - 6/(2*-32/50^2) = 3*50^2/32 = 2343.75 sec

H( 2343.75) = -32( 2343.75)/50^2 +6* 2343.75 + 200 = 70512.5 ft ( maximum height)

b) It takes 2343.75 sec reach max. height

c) To hit the ground

h(t) =0

-32t/50^2 + 6t +200 =0

t = -3.331 , 4690.831 sec to hit ground

neglect -ve value

t = 4690.831 sec to hit ground