Find the dimensions of a rectangle whose length is a foot lo

Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 20 feet. The length is feet. The width is feet.

Solution

let the width be x feet

So, length = 1 + 2 *x

Perimeter = 2 * (x + (1 + 2x))

or, 20 = 2 * (3x + 1)

or, 20 = 6x + 2

or, 6x = 18

or, x = 3

So, width = 3 feet and length = 1 + 2 * 3 = 7 feet