Assume that scores on the LSAT are approximately normally di

Assume that scores on the LSAT are approximately normally distributed in the population with a mean of 545 and a standard deviation of 110. What proportion of all people who take the exam score over 700?

A) .9207

B) .0793

C) .9500

D) .2061

E) The question cannot be answered from the information given.

Solution

Z=X-MEAN/SD

Z=(700-545)/110

Z=1.41

We take the value from the table of z

P(Z>1.41)=0.0793