Use Induction to prove 2 n2 n for all n ZSolutionTo prove
Solution
To prove that 2/ n2 +n by induction
step 1) to prove this for n=1
cinsider n2 +n = 12 +1
= 1+1
=2
and 2/2
therefore for n=1 give statement is true
step 2) Induction hypothysis
Aussum that statementb is for n=k
i.e 2/k2 +k
i.e 2/k(k+1)
step 3) to prove statement for n=k+1
consider
n2 +n = (k+1)2 +(k+1)
= (k+1)(k+1)+(k+1)
=(k+1)[(k+1)+1] comman k+1
=(k+1)(k+1+1)
=(k+1)(k+2)
=(k+2)(k+1)
n2 +n =k(k+1)+2(k+1)
since 2/k(k+1) by hypothysis
and 2/2(k+1) (because 2(k+1)is multiple of 2)
therfor 2 divid (k+1[k)+2(k+1)] i.e
2/(k+1[k)+2(k+1)]
therefor 2/n2 +n for n=k+1
therefor by induction hypothysis
2/n2 +n for all n in z+
