Use Induction to prove 2 n2 n for all n ZSolutionTo prove

Use Induction to prove 2 | n^2 + n for all n Z^+.

Solution

To prove that 2/ n2 +n by induction

step 1) to prove this for n=1

cinsider n2 +n = 12 +1

                     = 1+1

                       =2

and 2/2

therefore for n=1 give statement is true

step 2) Induction hypothysis

Aussum that statementb is for n=k

i.e 2/k2 +k

i.e 2/k(k+1)

step 3) to prove statement for n=k+1

consider

n2 +n = (k+1)2 +(k+1)

          = (k+1)(k+1)+(k+1)

          =(k+1)[(k+1)+1]                      comman k+1

          =(k+1)(k+1+1)

           =(k+1)(k+2)

           =(k+2)(k+1)

   n2 +n =k(k+1)+2(k+1)

since 2/k(k+1) by hypothysis

and 2/2(k+1)                         (because 2(k+1)is multiple of 2)

therfor 2 divid (k+1[k)+2(k+1)] i.e

2/(k+1[k)+2(k+1)]

therefor 2/n2 +n         for n=k+1

therefor by induction hypothysis

2/n2 +n   for all n in z+

 Use Induction to prove 2 | n^2 + n for all n Z^+.SolutionTo prove that 2/ n2 +n by induction step 1) to prove this for n=1 cinsider n2 +n = 12 +1 = 1+1 =2 and

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site