Let us find the degree of dissociation of CO2 at a fixed pre

Let us find the degree of dissociation of CO_2 at a fixed pressure and temperature CO_2 CO + 1/2 O_2 We know that the Gibbs free energy of a system is minimized at equilibrium. Write the full expression for the Gibbs free energy (G) of the gas^6. Now, let alpha be the degree of dissociation^7: you can write the G in terms of alpha by noting that when 1 - alpha moles of CO_2 dissociate, alpha moles of CO form and alpha/2 moles of O_2 form. Minimize this function and finds^8 alpha at 2500K and 1 atm. Also plot G as a function of alpha. Use the following values: Show that the value of alpha you found indeed corresponds to the minimum on the graph. What happens to alpha when the pressure decreases, increases^9? Why?

Solution

The answer of the following questions are as follows

The degree of dissociation of CO2 at fixed temperature and pressure is 0.045.

There is no change in the degree of dissociation because it depends upon total pressure.

 Let us find the degree of dissociation of CO_2 at a fixed pressure and temperature CO_2 CO + 1/2 O_2 We know that the Gibbs free energy of a system is minimize

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