DATA AND RESULTS 1612 M Concentration of Stock NaOH solution

DATA AND RESULTS: -1612 M Concentration of Stock NaOH solution: Standardization of the Stock acetic acid- Final buret reading: ducts )\" Lolo 120MA/3)Initial buret reading: mL Volume of NaOtH used:ml Calculated [HC,,o4asy Volume of NaOH used: 596 1 0% 25% 0% 75% 100% Final buret reading (mL) L6a Initial buret reading (mL) Volume NaOH used (mL) Total moles of Moles of HC2H,02 in aqueous- Moles of HC2H,O2 in organic [HC2H:02] in aqueous [HC H,O2) in Experimental Keq

Solution

Calculation for 5% solution

mol of HC2H3O2 in aqueous phase=mol of NaOH (titrant) [The titrant and HC2H3O2 react in 1:1molar ratio:

HC2H3O2 +NaOH--->NaC2H3O2 +H2O]

mol of NaOH=Molarity of NaOH*volume of NaOH=0.1012mol/L *0.0015L=0.000151mol

So,mol of HC2H3O2 in aqueous phase=0.000151mol

mol of HC2H3O2 in organic phase=total mol of HC2H3O2 -mol of HC2H3O2 in aqueous phase=0.00149mol-0.000151mol=0.00134mol

[HC2H3O2] in aqueous=mol in aq/total volume=0.000151mol/total volume of solution

[HC2H3O2] in organic=mol in aq/total volume=0.00149mol/total volume of solution

keq=[HC2H3O2] in organic/[HC2H3O2] in aq=0.00149/0.000151=9.867