If the heat of combustion for a specific compound is 10800 k

If the heat of combustion for a specific compound is -1080.0 kJ/mol and its molar mass is 35.17 g/mol, how many grams of this compound must you burn to release 181.70 kJ of heat?

Solution

Given that, 1mole= 35.17 g

Also heat released for combustion of 1 mole compound = 1080 k

i.e,

1080.0 kJ heat given by 35.17 g

181.7 kJ heat given by ? g

= 181.7×35.17/1080.0

= 5.917 g

Required compound = 5.917 g