Write the Canonical POS for F shown in the Truth Table Solut

Write the Canonical POS for F shown in the Truth Table.

Answer: Hence F=(a\'+b\'+c\') .(a\'+b+c\').(a+b\'+c\').(a+b\'+c).(a+b+c\')

Explanation: Take only the elements in the given truth table which gives output only with \'1\'. Then write the expression as above in products of sums form.

$Write the Canonical POS for F shown in the Truth Table. SolutionAnswer: Hence F=(a\'+b\'+c\') .(a\'+b+c\').(a+b\'+c\').(a+b\'+c).(a+b+c\') Explanation: Take on$

Write the Canonical POS for F shown in the Truth Table Solut

Solution

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