Could I get some help with this problem please Suppose that

Could I get some help with this problem please? Suppose that tan(t) = -3\\2 and that t is in quadrant IV. Find the exact value of sec(t) Thanks!

Solution

tan theta=-3/2

In fourth quadrant sec is positive.

sec2theta = 1 + tan2theta

sec2theta=1 + 9/4

sec2theta = 13/4

sec theta = (sqrt13)/2

Could I get some help with this problem please? Suppose that tan(t) = -3\\2 and that t is in quadrant IV. Find the exact value of sec(t) Thanks!Solutiontan thet

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