Could I get some help with this problem please Suppose that
Could I get some help with this problem please? Suppose that tan(t) = -3\\2 and that t is in quadrant IV. Find the exact value of sec(t) Thanks!
Solution
tan theta=-3/2
In fourth quadrant sec is positive.
sec2theta = 1 + tan2theta
sec2theta=1 + 9/4
sec2theta = 13/4
sec theta = (sqrt13)/2
