All the solutions Ive checked tell me that 2sin1321068 But m

All the solutions I\'ve checked tell me that 2sin(1)-3+2(1)=0.68.

But my calculator is giving me the value -0.965 when I plug in 1 for this.

Does anyone know what\'s going on?

I\'m trying to show that a root exists for f(x) between (0,1).

Here are the solutions:
http://answers.yahoo.com/question/index?qid=20090517222430AAY2gR4
http://www.chegg.com/homework-help/essential-calculus-1st-edition-chapter-1.r-problem-50e-solution-9780495014423

This can be if your calculator is in degree mode just change it to radan mode it will give correct result.

$All the solutions I\'ve checked tell me that 2sin(1)-3+2(1)=0.68. But my calculator is giving me the value -0.965 when I plug in 1 for this. Does anyone know wh$

All the solutions Ive checked tell me that 2sin1321068 But m

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