4 Find the zeros of the quadratic equation 3x2 10x 8 5 Use
4. Find the zeros of the quadratic equation: 3x^2 - 10x = 8
5. Use trigonometry to determine the following for a right triangle: For a 23degreesangle, the adjacent side = 2.5. How long is the hypotenuse?
6. Give the possible values of between 0 and 360o: sin = 1/2 = cos = -1 =
Solution
3x2-10x=8
3x2-10x-8=0
(3x+2)(x-4)=0
3x+2=0 , x-4=0
x=-2/3,4
5. Cos theta= adjacent/hypotenuse
Adjacent=2.5
Theta=23 degree
Cos 23=2.5/hypotenuse
Hypotenuse=2.5/cos 23=2.7
