4 Find the zeros of the quadratic equation 3x2 10x 8 5 Use

4. Find the zeros of the quadratic equation: 3x^2 - 10x = 8

5. Use trigonometry to determine the following for a right triangle: For a 23degreesangle, the adjacent side = 2.5. How long is the hypotenuse?

6. Give the possible values of between 0 and 360o: sin = 1/2 = cos = -1 =

Solution

3x2-10x=8

3x2-10x-8=0

(3x+2)(x-4)=0

3x+2=0 , x-4=0

x=-2/3,4

5. Cos theta= adjacent/hypotenuse

Adjacent=2.5

Theta=23 degree

Cos 23=2.5/hypotenuse

Hypotenuse=2.5/cos 23=2.7

4. Find the zeros of the quadratic equation: 3x^2 - 10x = 8 5. Use trigonometry to determine the following for a right triangle: For a 23degreesangle, the adjac

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