Sodium peroxide Na2O2 reacts with water to form sodium hydro

Sodium peroxide (Na₂O₂) reacts with water to form sodium hydroxide and oxygen gas. Write a balanced equation for the reaction and determine how much oxygen in grams is formed by the complete reaction of 35.23g of Na₂O₂.

Clearly label answer and provide all steps to receive points.

Solution

2Na2O2(S)+2H2O(l)=4NaOH(aq)+O2(g)

First convert grams of sodium peroxide to moles of sodium peroxide using the molar mass:

35.23g Na2O2 x (1mole Na2O2 / 77.98g Na2O2)= 0.45178moles Na2O2

You know that for every 2 moles of Na2O2 in the reaction, there is one mole of O2.

0.45178 moles Na2O2 x (1 mole O2 / 2 moles Na2O2) = 0.2259 moles O2

Convert to grams using molar mass:

0.2259 moles O2 x (32g O2 / 1 mole O2) = 7.228g O2