How many grams of aluminum may be formed by the passage of 6

How many grams of aluminum may be formed by the passage of 60,714 C through an electrolytic cell that contains a molten aluminum salt.

First convert the charge to Faradays

Q = 370C/ (96500 C/F) = 3.8341x10^-3 F

First convert the charge to Faradays

Q = 370C/ (96500 C/F) = 3.8341x10^-3 F

The reaction for the reduction of aluminium is thefollowing

Al³⁺ + 3e^- ----> Al(s)

3.834196x10^-3F xmol

Using the stoichiometric equation we make a rule of 3 to findout x.

x = (3.834169x10^-3)(1)/3 = 1.15025x10^-3mol

m = (1.15025x10^-3 mol)( 27 g/mol) = 0.034507 g