How many gallons of a 60 antifreeze solution must be mixed w

How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 50 antifreeze? Use the six-step method You need gallons. (Round to the nearest whole number)

Solution

Answer: 380 gallons (As explained below)

Let \'x\' be the gallons of 60% antifreeze solution to be mixed. Then,

(0.6)(x) + (0.15)(80) = 0.5(100 + x)
0.6x + 12 = 50 + 0.5x
0.6x - 0.5x = 50 - 12
0.1x = 38
x = 35 / 0.1 = 380 gallons.