Use tables to fill in the blanks in the chart below for wate
Solution
For the 1st Row:
The quality is x = 0.2 which implies that water is in saturated mixture state.
Pressure, P = 200 kPa belongs to saturation temperature Tsat = 120.23°C, for the values over hf = 504.7 kJ/kg and hfg = 2201.9 kJ/kg from the table of saturated mixture.
Therefore, enthalpy h can be represented as, h = hf + xhfg = 504.7 + 0.2*2201.9 = 945.08 kJ/kg.
For the 2nd Row:
At T = 140°C and h = 1800 kJ/kg the enthalpy value lies between hf = 589.13 kJ/kg and hfg = 2144.7 kJ/kg.
Therefore, water is in saturated mixture state and its quality can be represented as:
x = (h - hf)/hfg = (1800 - 589.13)/2144.7 = 0.5645
3rd Row:
The quality x = 0 belongs to saturated liquid phase of water.
At pressure P = 950kPa, the saturation temperature is Tsat = 177.69°C and enthalpy h = hf = 753.02 kJ/kg.
4th Row:
For pressure P = 500 kPa and Temperature T = 80°C data is not sufficient.
5th Row:
For pressure P = 800kPa and enthalpy h = 3162.6 kJ/kg which is greater that hg, water is in supearheated vapour state.
Therefore the saturation temperature for this case will be Tsat = 350°C and water quality is not needed or applicable.
