A voltaic cell consists of an AlAl3 halfcell and a AgAg half
A voltaic cell consists of an Al/Al3+ half-cell and a Ag/Ag+ half-cell. Calculate [Al3+] when [Ag+] = 1.1526 M and Ecell = 2.445 V.
Use reduction potential values of Al3+ = -1.66 V and for Ag+ = +0.80 V.
Use scientific (E) notation with 2 numbers after the decimal point.
answer I got is 8.81 so i want to make sure im right or wrong plzz if im wrong give me the correct answer THANKS :D
Solution
Eocell = 0.8+1.66 = 2.46 V
Al + 3Ag+ --> 3Ag + Al3+
Ecell =2.445
Ecell = E0cell - (0.059/3)ln(1.1526/[Ag+]^3)
[Ag+] = 0.813 M
![A voltaic cell consists of an Al/Al3+ half-cell and a Ag/Ag+ half-cell. Calculate [Al3+] when [Ag+] = 1.1526 M and Ecell = 2.445 V. Use reduction potential valu A voltaic cell consists of an Al/Al3+ half-cell and a Ag/Ag+ half-cell. Calculate [Al3+] when [Ag+] = 1.1526 M and Ecell = 2.445 V. Use reduction potential valu](/WebImages/45/a-voltaic-cell-consists-of-an-alal3-halfcell-and-a-agag-half-1143215-1761613666-0.webp)