A voltaic cell consists of an AlAl3 halfcell and a AgAg half

A voltaic cell consists of an Al/Al3+ half-cell and a Ag/Ag+ half-cell. Calculate [Al3+] when [Ag+] = 1.1526 M and Ecell = 2.445 V.
Use reduction potential values of Al3+ = -1.66 V and for Ag+ = +0.80 V.
Use scientific (E) notation with 2 numbers after the decimal point.

answer I got is 8.81 so i want to make sure im right or wrong plzz if im wrong give me the correct answer THANKS :D

Solution

Eocell = 0.8+1.66 = 2.46 V

Al + 3Ag+ --> 3Ag + Al3+

Ecell =2.445

Ecell = E0cell - (0.059/3)ln(1.1526/[Ag+]^3)

[Ag+] = 0.813 M

A voltaic cell consists of an Al/Al3+ half-cell and a Ag/Ag+ half-cell. Calculate [Al3+] when [Ag+] = 1.1526 M and Ecell = 2.445 V. Use reduction potential valu

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