PLEASE ANSWER ALL Given that fx sin x gx cos x and hx tan x

PLEASE ANSWER ALL!

Given that f(x) sin x, g(x) cos x, and h(x) tan x, evaluate the given function. The point (x 3), on the circle x2 y also lies on the terminal side of an angle a in quadrant ll. The point y on the circle x2 y2-1, also lies on the terminal side of an angle B n quadrant lli. g(2a) 4

Solution

2)   sin = -4/5

      cos = sqrt[1 – sin^2] = 3/5

     tan = -4/3

    Now   tan(2) = 2*tan/[1 + tan^2] = (-8/3)/(25/9) = -24/25

3)   cos = 15/17

      sin = sqrt[1 – cos^2] = -8/17

    Now   sin(2) = 2*sin*cos = -240/289 (First option)

4)   csc = 1/sin = 25/24

      Sin = 24/25

      cos = sqrt[1 – sin^2] = -7/25

      tan = -24/7

     Now   cos(2) = (1 – tan^2)/[1 + tan^2] = -527/625 (Last option)

5) csc = 1/sin = -4/3

      Sin = -3/4

      cos = sqrt[1 – sin^2] = -7/4

      tan = 3/7

      Now cos = 2*cos^2(/2) – 1 = -7/4

     cos^2(/2) = (-7 + 4)/8

      cos(/2) = -sqrt[(-7 + 4)/8]