FDC Red 40 Allura Red Ci8H14N2Na08s Mw 49643 25900 at 505 n

FD&C; Red #40 (Allura Red) Ci8H14N2Na,08s, Mw =496.43 = 25,900 (at 505 nm) FD&C; Blue #1 (Neptune Blue) C37He3N2Na O,S MW-792.84 = 130,000 (at 630 nm) Fraction Numbers Combined Total Volume (mL) 18.4 mL 0.392 0.82 20.2 mL 0.148 0.31 Absorbance Concentration [4.1 or 4.2] moles of dye in 5.0 mL [4.3] mg of dye in 5.0 mL [4.4] 0 mg of dye in one can (355 mL) [4.4] mg of dye in one 2.0L bottle (4.4]

Solution

Analysis of dye

FD&C Red

Molarity = 0.82 M

Volume = 18.4 ml

So,

moles of dye in 5 ml = 0.82 M x 18.4 ml = 15.088 mmol

mg of dye in 5 ml = 15.088 mmol x 496.43 g/mol = 7490.136 mg

mg of due in one can = 7490.136 mg x 355 ml/5 ml = 5.32 x 10^5 mg

mg of dye in one bottle = 5.32 x 10^5 mg x 2 L/0.355 L = 3 x 10^6 mg

-

FD&C Blue

Molarity = 0.31 M

Volume = 20.2 ml

So,

moles of dye in 5 ml = 0.31 M x 20.2 ml = 6.262 mmol

mg of dye in 5 ml = 6.262 mmol x 792.84 g/mol = 4964.764 mg

mg of due in one can = 4964.764 mg x 355 ml/5 ml = 3.52 x 10^5 mg

mg of dye in one bottle = 3.52 x 10^5 mg x 2 L/0.355 L = 2 x 10^6 mg