The data represent the ages of 20 customers who ordered a pr

The data represent the ages of 20 customers who ordered a product advertised on television. Find the mean and standard deviation of the variable. Round your answers to one decimal place as needed.

Solution

Getting the mean, X,          
          
X = Sum(x) / n          
Summing the items, Sum(x) =    921      
As n =    20      
Thus,          
X =    46.05   [ANSWER, MEAN]

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Setting up tables,          

  

Thus, Sum(x - X)^2 =    4454.95      
          
Thus, as           
          
s^2 = Sum(x - X)^2 / (n - 1)          
          
As n =    20      
          
s^2 =    234.4710526      
          
Thus,          
          
s =    15.31244764   [ANSWER, STANDARD DEVIATION]  

x	x - X	(x - X)^2
50	3.95	15.6025
61	14.95	223.5025
48	1.95	3.8025
52	5.95	35.4025
35	-11.05	122.1025
32	-14.05	197.4025
69	22.95	526.7025
48	1.95	3.8025
10	-36.05	1299.603
28	-18.05	325.8025
63	16.95	287.3025
36	-10.05	101.0025
41	-5.05	25.5025
27	-19.05	362.9025
60	13.95	194.6025
36	-10.05	101.0025
50	3.95	15.6025
63	16.95	287.3025
64	17.95	322.2025
48	1.95	3.8025