At a certain temperature a 210L contains holds four gases in

At a certain temperature, a 21.0-L contains holds four gases in equilibrium. Their masses are 3.5 g SO3, 4.6 g SO2, 21.8 g N2, and 0.98 g N20 What is the value of the equilibrium constant at this temperature for the reaction of SO2 with N2O to fornm SO3 and N2 (balanced with lowest whole-number coefficients)? Number

Solution

1)

SO2 + N2O ------> SO3 + N2

Kc = [SO3][N2]/[SO2][N2O]

Kc = (3.5/80*1/21)(21.8/28*1/21)/((4.6/64*1/21)*(0.98/44*1/21))

Kc = 21.278

2)

[H+] = 1.6 * 10^-7

pH = -log[H+] = -log(1.6*10^-7) = 6.795

pOH = 14 - pH = 14 - 6.795 = 7.205

pOH = 7.205

[OH-] = 10^-7.205

[OH-] = 6.237 * 10^-8

3)

[H3O+] = 0.00657

pH = -log[H3O+] = -log(6.57 * 10^-3)

pH = 2.1824

pOH = 14 - pH = 14 - 2.1824 = 11.8176

[OH-] = 10^-11.8176 = 1.5219 * 10^-12