Based on the given van der Waals constants for four hypothet

Based on the given van der Waals constants for four hypothetical gases (G1, G2, G3, G4), arrange these hypothetical gases in order of decreasing strength of intermolecular forces. Assume that the gases have similar molar masses.

Rank from strongest to weakest intermolecular attraction. To rank items as equivalent, overlap them.

Gas 3, Gas 2, Gas 1, Gas 4

Gas G1 G2 G3 G4 2am/mol2) L/mol) 0.0289 0.0388 0.0467 0.0310 2 5.22 1.05 2.31 4.05

Solution

The strength of intermolecular forces is measured in terms of the parameter a. Now, the higher the value of the parameter a , the higher is the strength of interactions. So, in terms of decreasing strength of intermolecular forces, the gases can be arranged as follows

5.22>4.05>2.31>1.05

So, Gas1> Gas4> Gas3>Gas2