Which is the polar form of the parametric equations x 4t an

Which is the polar form of the parametric equations x = 4t and t = t^2? r = 16 tan theta sec theta r = 16 tan^2 theta r = 16 sec^2 theta r = 16 sec theta

Solution

x=4t , y=t²

t=x/4   ,   y=x²/16

16rsin theta=r²cos²theta

r=16 sin theta/cos²theta = 16 (sin theta /cos thet)(1/cos theta) = 16tan theta sec theta

option first