What is Y 2 log k5x11Solution We have Y 2 log k5x11 so t

What is: Y = 2 + log (k+5^(x+11))

We have Y = 2 + log (k+5^(x+11)) so that Y-2 = log (k+5^(x+11)) and hence k + 5^(x+11) = 10^Y-2 , or, 5^(x+11) = 10^Y-2 –k. On taking logarithm of both the sides, we have (x +11) log 5 = log(10^Y-2 –k) so that x + 11 = log(10^Y-2 –k)/ log 5= [log(10^Y-2 –k) ] / 0.6990 (approximately) . Hence x = 1/0.6990[log(10^Y-2 –k) ] -11.