There is a 086 probability that MATH 106 students will corre

There is a 0.86 probability that MATH 106 students will correctly follow all instructions on the Final Exam. What is the probability that exactly 86 of the 100 students taking MATH 106 in a particular term correctly follow all Final Exam instructions? Round answer to the nearest ten thousandth

Solution

Lets assume test takings are independent events i.e the probability of me following instructions will not influence you following instructions.

We use binomial distribution to find probability:

P(86) = 100C86(0.86)^86(1-0.86)^14

= 0.1142