In the following reaction COg Clg COCl2g the CO is 00102 M

In the following reaction


CO(g) + Cl(g)----> COCl2(g)

the [CO] is 0.0102 M and [Cl2] is 0.00609 M initally. At equilibrium [Cl2] is 0.00301 M. Calculate Kc.

Solution

CO(g) + Cl2(g) ---------------> COCl2(g)

0.0102 0.00609 0

at eqb

0.0102-x   0.00609-x x


At equilibrium [Cl2] is 0.00301 M

therefore


0.00609-x = 0.00301

x =0.00308


at eqb

[CO] = 0.00712 M

[Cl2] = 0.00301 M

[COCl2] = 0.00308 M


Kc =[COCl2]/([CO]*[Cl2])

=143.716 M^-1



In the following reaction CO(g) + Cl(g)----> COCl2(g) the [CO] is 0.0102 M and [Cl2] is 0.00609 M initally. At equilibrium [Cl2] is 0.00301 M. Calculate Kc.S

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site