For the IEEE Std 7541935 single precision floating point num
Solution
a) and b)
 scope of exponents and exponents bias:
range of exponents: -126 to +127
rane of biased exponents : 1 to 254 (0 and 255 are reserverd i.e. 00000000 and 11111111)
above ranges are calculated by considering reserved 00000000 and 11111111.
c)scope of fraction part:
there are 23 bits for mantissa so we have range of 2^23 = 8388608
d)how to represent 0 in ieee 754 std:
 sign = 0 for positive zero, 1 for negative zero.
 biased exponent = 0.
 fraction = 0.
e)infinities and NaN
 infinities:
 sign = 0 for positive infinity, 1 for negative infinity.
 biased exponent = all 1 bits.
 fraction = all 0 bits.
NaN:
 sign = either 0 or 1.
 biased exponent = all 1 bits.
 fraction = anything except all 0 bits (since all 0 bits represents infinity).
f)smallest positive value
considered denormalised number.
Exponent bitstring 08. It\'s value is -126.
 The fraction is (022)1, i.e., 22 zeroes followed by a single 1.
 This looks like:
 S Exp Fraction
 - --------- ----------------------------
 0 0000 0000 0000 0000 0000 0000 0000 001
This bitstring pattern maps to the number 0.0221 x 2-126, which is 1.0 x 2-149
g)largest positive value:
 the fraction is 123. It looks like:
 S Exp Fraction
 - --------- ----------------------------
 0 0000 0000 1111 1111 1111 1111 1111 111
 This bitstring maps to the number 0.(123) x 2-126. This number has 23 bits of precision, since there are 23 1\'s after the radix point.
h)
 -0.75 in IEEE std.
 binary representation: 10111111010000000000000000000000
i)
 1/3 in IEEE std:
 closest value:
 00111110101010001111010111000011


