A farmer buys 3 cows 2 pigs and 4 hens from a man who has 6

A farmer buys 3 cows, 2 pigs and 4 hens from a man who has 6 cows, 5 pigs and 8 hens. How many choices does the former have? Justify your answer

Solution

Since choosing of cow is independent of pig and hens, hence the total number of choices will be given by the multiplication of individual possibilities

Number of ways = Choosing 3 cows from 6 cows * Choosing 2 pigs from 5 pigs * Choosing 4 hens from 8 hens

=> 6C3 * 5C2 * 8C4

=> 20 * 10 * 70

=> 14000 ways