Use backsubstitution to solve the triangular system 2x y 4
Use back-substitution to solve the triangular system. {2x - y + 4z = 3 y + 3z = 0 -2z = 1 (x, y) = ()
Solution
2x - y +3z = 3
y +2z =0
-2z = 1
So, we have z = -1/2
substituting in equation 2:
y -1 =0 ; y = 1
Now substitute value of y and z in equation 1 :
2x - 1 +4(-1/2) =3
2x - 1 - 2 =3
2x = 6
x = 2
(x , y z ) = ( 2 , 1 , -1/2)
