What is the pH of a neutral solution at a temperature where

What is the pH of a neutral solution at a temperature where Kw=9.9×1014?

Express your answer numerically using two decimal places.

What is the pH of a neutral solution at a temperature where Kw=9.9×1014?

Express your answer numerically using two decimal places.

Solution

for a neutral solution

[H+] = [OH-]

now

[H+] [OH-] = Kw

[H+] [H+] = 9.9 x 10-14

[H+]^2 = 9.9 x 10-14

[H+] = sqrt (9.9 x 10-14)

[H+] = 3.1464 x 10-7

now

pH = -log [H+]

pH = -log (3.1464 x 10-7)

pH = 6.502

so

the pH of the neutral solution is 6.50