An electric circuit with a 50 V EMF oscillating at 60 rads c

An electric circuit with a 50 V EMF oscillating at 60 rad/s contains a single inductor with self-inductance L_1 = 20 mH. A second electric circuit contains an inductor with self-inductance L_2 = 10 mH and a resistor with resistance R = 4 Ohm. These two circuits have a mutual inductance M = 5 mH. What is the average power (in W) supplied by the EMF?

Solution

Given

Omega = 60 rad/sec

w,k,t,

Omega = (2*pi/t)

t= 0.10 sec

The formula for power is:

P= EI

E =(L1+L2+2M) (dI/dt)

(dI/dt) =E/ (L1+L2+2M)

Integrating w.r.t \"t\" and limits would be 0 to 0.10

I = 1.25 mA

Therefore average power is,

P= EI

P =62.5 mW.