1 10 pts The molar mass of phenolphthalein an acidbase indic
Solution
Ans. Given, osmotic pressure, P = 14.6 mm Hg = (14.6 / 760) atm = 0.01921 atm
Mass of phenolphthalein = 500.0 mg = 0.500 g
# Let the molar mass of phenolphthalein = X g/ mol
So,
Moles of phenolphthalein = Mass/ Molar mass
= 0.500 g / (X g / mol)
= (0.5 / X) mol
Now,
Molarity of solution = Moles / Volume of solution in liters
= (0.5/ X) mol / 2.0 L
= (0.25/X) M
# Osmotic pressure, P of a solution in given by-
P = i x MRT - equation 1
Where,
i = van’t Hoff factor = 1 for non-ionizing solutes
M = molarity of solution
R = gas constant = 0.0821 atm L mol-1K-1 = 0.0821 atm M-1K-1
T = temperature in kelvin = (0C + 273.05)K
Putting the values in equation 1-
0.01921 atm = 1 x (0.25/X) M x (0.0821 atm M-1K-1) x 298.15 K
Or, 0.01921 atm = (6.11952875 / X) atm
Or, X = 6.11952875 atm / 0.01921 atm
Hence, X = 318.56
Therefore, molar mass of phenolphthalein = X g/ mol = 318.56 g/ mol
