Let U be a supspace in V Let V1 Vk be a basis of V Let W1
Let U be a supspace in V, Let {V_1, ..., V_k} be a basis of V Let {W_1, ..., W_s} elementof V. Then prove that {[w_1, ..., [w_s]]} is linearly independent in V/V if and only if {V_1, V_k, W_1, ....W_s} is linearly independent in V.
Solution
Definition of Linearly independent vector is
v1 , v2----vn are LI vectors if and only if
the eqn a1v1+ a2v2+-----anvn=0 => all ai =0------(1)
v1 , v2---vk form the basis of the subspace U ( hence these k vectors are LI) ----(2)
the above k vectors and some more LI vectors form the basis of V
w1, w2 -----ws are LI in V/U if and only if the k vectors in \'2\' and these \'s vectors form the basis of V
ie v1 ,v2 ---vn , w1 , w2 ---wn form the basis of the vector space V and hence these vectors ae LI
![Let U be a supspace in V, Let {V_1, ..., V_k} be a basis of V Let {W_1, ..., W_s} elementof V. Then prove that {[w_1, ..., [w_s]]} is linearly independent in V Let U be a supspace in V, Let {V_1, ..., V_k} be a basis of V Let {W_1, ..., W_s} elementof V. Then prove that {[w_1, ..., [w_s]]} is linearly independent in V](/WebImages/46/let-u-be-a-supspace-in-v-let-v1-vk-be-a-basis-of-v-let-w1-1145634-1761615648-0.webp)