What is the mole fraction of solute and the molal concentrat

What is the mole fraction of solute and the molal concentration for an aqueous solution that is 11.0% NaOH by mass?

mole fraction x=

molality m=

let total mass =M

mass of NaOH=11*M

mole fraction =(11M/40)/(11M/40 +89*M/18) =0.0526

molality= (11*M/40)/(89M*10^-3) =3.089 m

$What is the mole fraction of solute and the molal concentration for an aqueous solution that is 11.0% NaOH by mass? mole fraction x= molality m=Solutionlet tot$

What is the mole fraction of solute and the molal concentrat

Solution

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