Find missing parts of triangle C 122 deg a 63 m b 102 m Fin

Find missing parts of triangle

C= 122 deg

a = 6.3 m

b= 10.2 m

Find missing parts of triangle

C= 122 deg

a = 6.3 m

b= 10.2 m

C= 122 deg

a = 6.3 m

b= 10.2 m

c^2=a^2+b^2-2abcosC

c^2=39.69+104.04-128.52cos122

c=14.6m

sinC/c=sinB/b

sin122/14.6=sinB/10.2

B=36.3°

A=180-B-C=21.7°

Find missing parts of triangle C= 122 deg a = 6.3 m b= 10.2 m Find missing parts of triangle C= 122 deg a = 6.3 m b= 10.2 m C= 122 deg a = 6.3 m b= 10.2 mSolut

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