Given Cx 1200 1000x and Rx 1200x x2 Find the cost C of p

Given: C(x) = 1200 + 1000x and R(x) = 1200x - x^2) Find the cost C of producting x units of a product and the revenue R from selling x units of the same product. The profit function P is equal to R - c. which of the following defines the function P? a) P(x) = x^2 - 200x +1200 b) P(x) = x^2 + 200x - 1200 c) P(x) = x^2 + 200x - 1200 d) P(x) = x^2 + 2200x - 1200 e) P(x) = x^2 + 2200x +1200

Solution

The profit function is P(x)=R(x)-C(x) where C(x) and R(x) are the cost and revenue whose equations are given.   

To find P(x) put the equations of R and C in the above expression P=R-C.

Therefe, P(x)=(1200x-x^2)-(1200+1000x)

P(x)=1200x-x^2-1200-1000x

P(x)=-x^2+1200x-1000x-1200

P(x)=-x^2+200x-1200

This is the right answer..